# Rabi Basis

Previously I have ignored the oscillating $\sigma_3$ terms in the Hamiltonian such as in Eqn. \eqref{chap:matter-sec:single-fequency-eq:hamiltonian-bg-matter-basis-single-frequency}. Using the Jacobi-Anger expansion, J. Kneller et al. showed that these terms result in an infinite number of resonance conditions. In the rest of the chapter, I will present a much simpler derivation of their results from the perspective of Rabi oscillations. For this purpose I will define a new basis called Rabi basis $$$$\begin{pmatrix} \ket{\nu_{\mathrm{r1}}}\\ \ket{\nu_{\mathrm{r2}}} \end{pmatrix} = \mathsf{U}^\dagger \begin{pmatrix} \ket{\nu_{\mathrm{L}}} \\ \ket{\nu_{\mathrm{H}}} \end{pmatrix}, \label{eq-rabi-basis}$$$$ where $$$$\mathsf{U} = \begin{pmatrix} e^{-\ri \eta (r)} & 0 \\ 0 & e^{\mathrm i \eta (r)} \end{pmatrix}. \label{eq-rabi-transformation}$$$$ The unitary transformation in Eqn.~\eqref{eq-rabi-transformation} is a rotation in flavor space about the third axis. It commutes with $\sigma_3$ terms in the Hamiltonian, but, due to its dependence on $r$, the left side of the Schr"{o}dinger equation obtains an extra term: \begin{align*} &\begin{pmatrix} \frac{\mathrm d\eta}{\mathrm dr} & 0 \\ 0 & - \frac{\mathrm d\eta}{\mathrm d r} \end{pmatrix} \begin{pmatrix} \psi_{\mathrm R1} \\ \psi_{\mathrm R2} \end{pmatrix} + \mathrm i \frac{\mathrm d}{\mathrm dr} \begin{pmatrix} \psi_{\mathrm R1} \\ \psi_{\mathrm R2} \end{pmatrix} \\ =& \left[ -\frac{\omega_{\mathrm m} }{2} \sigma_3 + \frac{\delta \lambda}{2} \cos 2\theta_{\mathrm m} \sigma_3 - \frac{\delta \lambda}{2} \sin 2\theta_{\mathrm m} \begin{pmatrix} 0 & e^{2\mathrm i\eta} \\ e^{-2 \mathrm i\eta } & 0 \end{pmatrix} \right] \begin{pmatrix} \psi_{\mathrm R1} \\ \psi_{\mathrm R2} \end{pmatrix}. \end{align*} The oscillating $\sigma_3$ terms in Hamiltonian can be eliminated by choosing $\eta(r)$ properly, i.e., $$$$\eta(r) - \eta(0) = \frac{\cos 2\theta_{\mathrm{m}}}{2} \int_0^r \delta\lambda (\tau) \dd\tau.$$$$ With this definition, the Schr"{o}dinger equation simplifies: $$$$\ri \frac{\dd}{\dd r} \begin{pmatrix} \psi_{\mathrm r1} \\ \psi_{\mathrm r2} \end{pmatrix} = \left[ - \frac{\omega_{\mathrm m}}{2} \sigma_3 - \frac{\delta \lambda}{2} \sin 2\theta_{\mathrm m} \begin{pmatrix} 0 & e^{2\ri\eta} \\ e^{-2 \ri \eta } & 0 \end{pmatrix}\right] \begin{pmatrix} \psi_{\mathrm r1} \\ \psi_{\mathrm r2} \end{pmatrix}. \label{chap:matter-sec:jacobi-subsec:rabi-basis-eqn:eom-rabi-basis-matter}$$$$ Because the states $\ket{\nu_{r1}}$ and $\ket{\nu_{r2}}$ are related to $\ket{\nu_{\mathrm L}}$ and $\ket{ \nu_{\mathrm H} }$ by phase factors only, the transition probability between the former two states is the same as that between the latter.